Integrand size = 31, antiderivative size = 98 \[ \int \frac {\cos ^2(c+d x) (A+B \sec (c+d x))}{a+a \sec (c+d x)} \, dx=\frac {(3 A-2 B) x}{2 a}-\frac {2 (A-B) \sin (c+d x)}{a d}+\frac {(3 A-2 B) \cos (c+d x) \sin (c+d x)}{2 a d}-\frac {(A-B) \cos (c+d x) \sin (c+d x)}{d (a+a \sec (c+d x))} \]
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Time = 0.18 (sec) , antiderivative size = 98, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.161, Rules used = {4105, 3872, 2715, 8, 2717} \[ \int \frac {\cos ^2(c+d x) (A+B \sec (c+d x))}{a+a \sec (c+d x)} \, dx=-\frac {2 (A-B) \sin (c+d x)}{a d}+\frac {(3 A-2 B) \sin (c+d x) \cos (c+d x)}{2 a d}-\frac {(A-B) \sin (c+d x) \cos (c+d x)}{d (a \sec (c+d x)+a)}+\frac {x (3 A-2 B)}{2 a} \]
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Rule 8
Rule 2715
Rule 2717
Rule 3872
Rule 4105
Rubi steps \begin{align*} \text {integral}& = -\frac {(A-B) \cos (c+d x) \sin (c+d x)}{d (a+a \sec (c+d x))}+\frac {\int \cos ^2(c+d x) (a (3 A-2 B)-2 a (A-B) \sec (c+d x)) \, dx}{a^2} \\ & = -\frac {(A-B) \cos (c+d x) \sin (c+d x)}{d (a+a \sec (c+d x))}+\frac {(3 A-2 B) \int \cos ^2(c+d x) \, dx}{a}-\frac {(2 (A-B)) \int \cos (c+d x) \, dx}{a} \\ & = -\frac {2 (A-B) \sin (c+d x)}{a d}+\frac {(3 A-2 B) \cos (c+d x) \sin (c+d x)}{2 a d}-\frac {(A-B) \cos (c+d x) \sin (c+d x)}{d (a+a \sec (c+d x))}+\frac {(3 A-2 B) \int 1 \, dx}{2 a} \\ & = \frac {(3 A-2 B) x}{2 a}-\frac {2 (A-B) \sin (c+d x)}{a d}+\frac {(3 A-2 B) \cos (c+d x) \sin (c+d x)}{2 a d}-\frac {(A-B) \cos (c+d x) \sin (c+d x)}{d (a+a \sec (c+d x))} \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(197\) vs. \(2(98)=196\).
Time = 1.53 (sec) , antiderivative size = 197, normalized size of antiderivative = 2.01 \[ \int \frac {\cos ^2(c+d x) (A+B \sec (c+d x))}{a+a \sec (c+d x)} \, dx=\frac {\cos \left (\frac {1}{2} (c+d x)\right ) \sec \left (\frac {c}{2}\right ) \left (4 (3 A-2 B) d x \cos \left (\frac {d x}{2}\right )+4 (3 A-2 B) d x \cos \left (c+\frac {d x}{2}\right )-20 A \sin \left (\frac {d x}{2}\right )+20 B \sin \left (\frac {d x}{2}\right )-4 A \sin \left (c+\frac {d x}{2}\right )+4 B \sin \left (c+\frac {d x}{2}\right )-3 A \sin \left (c+\frac {3 d x}{2}\right )+4 B \sin \left (c+\frac {3 d x}{2}\right )-3 A \sin \left (2 c+\frac {3 d x}{2}\right )+4 B \sin \left (2 c+\frac {3 d x}{2}\right )+A \sin \left (2 c+\frac {5 d x}{2}\right )+A \sin \left (3 c+\frac {5 d x}{2}\right )\right )}{8 a d (1+\cos (c+d x))} \]
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Time = 0.89 (sec) , antiderivative size = 61, normalized size of antiderivative = 0.62
method | result | size |
parallelrisch | \(\frac {\left (A \cos \left (2 d x +2 c \right )+\left (-2 A +4 B \right ) \cos \left (d x +c \right )-7 A +8 B \right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )+6 d \left (A -\frac {2 B}{3}\right ) x}{4 d a}\) | \(61\) |
derivativedivides | \(\frac {-\tan \left (\frac {d x}{2}+\frac {c}{2}\right ) A +\tan \left (\frac {d x}{2}+\frac {c}{2}\right ) B +\frac {2 \left (-\frac {3 A}{2}+B \right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}+2 \left (-\frac {A}{2}+B \right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{\left (1+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right )^{2}}+\left (3 A -2 B \right ) \arctan \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d a}\) | \(100\) |
default | \(\frac {-\tan \left (\frac {d x}{2}+\frac {c}{2}\right ) A +\tan \left (\frac {d x}{2}+\frac {c}{2}\right ) B +\frac {2 \left (-\frac {3 A}{2}+B \right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}+2 \left (-\frac {A}{2}+B \right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{\left (1+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right )^{2}}+\left (3 A -2 B \right ) \arctan \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d a}\) | \(100\) |
norman | \(\frac {\frac {\left (3 A -2 B \right ) x \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}}{a}+\frac {\left (3 A -2 B \right ) x}{2 a}-\frac {\left (A -B \right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{5}}{a d}-\frac {\left (2 A -3 B \right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{a d}+\frac {\left (3 A -2 B \right ) x \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{4}}{2 a}-\frac {\left (5 A -4 B \right ) \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}{a d}}{\left (1+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}\right )^{2}}\) | \(152\) |
risch | \(\frac {3 A x}{2 a}-\frac {x B}{a}+\frac {i A \,{\mathrm e}^{i \left (d x +c \right )}}{2 a d}-\frac {i {\mathrm e}^{i \left (d x +c \right )} B}{2 a d}-\frac {i A \,{\mathrm e}^{-i \left (d x +c \right )}}{2 a d}+\frac {i {\mathrm e}^{-i \left (d x +c \right )} B}{2 a d}-\frac {2 i A}{d a \left ({\mathrm e}^{i \left (d x +c \right )}+1\right )}+\frac {2 i B}{d a \left ({\mathrm e}^{i \left (d x +c \right )}+1\right )}+\frac {A \sin \left (2 d x +2 c \right )}{4 a d}\) | \(156\) |
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Time = 0.27 (sec) , antiderivative size = 81, normalized size of antiderivative = 0.83 \[ \int \frac {\cos ^2(c+d x) (A+B \sec (c+d x))}{a+a \sec (c+d x)} \, dx=\frac {{\left (3 \, A - 2 \, B\right )} d x \cos \left (d x + c\right ) + {\left (3 \, A - 2 \, B\right )} d x + {\left (A \cos \left (d x + c\right )^{2} - {\left (A - 2 \, B\right )} \cos \left (d x + c\right ) - 4 \, A + 4 \, B\right )} \sin \left (d x + c\right )}{2 \, {\left (a d \cos \left (d x + c\right ) + a d\right )}} \]
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\[ \int \frac {\cos ^2(c+d x) (A+B \sec (c+d x))}{a+a \sec (c+d x)} \, dx=\frac {\int \frac {A \cos ^{2}{\left (c + d x \right )}}{\sec {\left (c + d x \right )} + 1}\, dx + \int \frac {B \cos ^{2}{\left (c + d x \right )} \sec {\left (c + d x \right )}}{\sec {\left (c + d x \right )} + 1}\, dx}{a} \]
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Leaf count of result is larger than twice the leaf count of optimal. 225 vs. \(2 (94) = 188\).
Time = 0.30 (sec) , antiderivative size = 225, normalized size of antiderivative = 2.30 \[ \int \frac {\cos ^2(c+d x) (A+B \sec (c+d x))}{a+a \sec (c+d x)} \, dx=-\frac {A {\left (\frac {\frac {\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} + \frac {3 \, \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}}}{a + \frac {2 \, a \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}} + \frac {a \sin \left (d x + c\right )^{4}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{4}}} - \frac {3 \, \arctan \left (\frac {\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1}\right )}{a} + \frac {\sin \left (d x + c\right )}{a {\left (\cos \left (d x + c\right ) + 1\right )}}\right )} + B {\left (\frac {2 \, \arctan \left (\frac {\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1}\right )}{a} - \frac {2 \, \sin \left (d x + c\right )}{{\left (a + \frac {a \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}}\right )} {\left (\cos \left (d x + c\right ) + 1\right )}} - \frac {\sin \left (d x + c\right )}{a {\left (\cos \left (d x + c\right ) + 1\right )}}\right )}}{d} \]
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Time = 0.28 (sec) , antiderivative size = 123, normalized size of antiderivative = 1.26 \[ \int \frac {\cos ^2(c+d x) (A+B \sec (c+d x))}{a+a \sec (c+d x)} \, dx=\frac {\frac {{\left (d x + c\right )} {\left (3 \, A - 2 \, B\right )}}{a} - \frac {2 \, {\left (A \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - B \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )}}{a} - \frac {2 \, {\left (3 \, A \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 2 \, B \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + A \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 2 \, B \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 1\right )}^{2} a}}{2 \, d} \]
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Time = 13.86 (sec) , antiderivative size = 107, normalized size of antiderivative = 1.09 \[ \int \frac {\cos ^2(c+d x) (A+B \sec (c+d x))}{a+a \sec (c+d x)} \, dx=\frac {x\,\left (3\,A-2\,B\right )}{2\,a}-\frac {\left (3\,A-2\,B\right )\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^3+\left (A-2\,B\right )\,\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}{d\,\left (a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4+2\,a\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+a\right )}-\frac {\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\,\left (A-B\right )}{a\,d} \]
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